The perimeter of the adjoining trapezium is :
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DE = 12cm
by Pythagoras theoram we find that
DB^2 = DE^2+BE^2
13^2 = 12^2 + BE^2
169= 144+ BE^2
169-144= BE^2
25 = BE^2
BE = 5
AB = AE+BE
AB = 9 + 5
AB = 14
perimeter = 14+12+13+9
perimeter = 48
pleasehelpme000:
No there is not an option 39
Only there are 44 46 52 48
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