The perimeter of the ends of a frustum of a cone are 44 cm and 8.4 π cm. If the depth
is 14 cm, then find its volume.
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Answer:
Perimeter=2πr.
44=2×22/7 × r
44/2 × 7/22=r
r=7cm.
Perimeter=2πr
8.4π=2πr
r=4.2cm.
Volume of frustum= 1/3 πh(r1² + r2² + r1×r2)
=> 1/3×22/7×14(49+17.64+29.4)
=>1/3×22×2(96.04)
=>1/3×44×96.04
=>1/3×4225.76
=>1408.5866cm³.
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