Math, asked by ekta8817, 4 months ago



The perimeter of the equilateral triangle XYZ is 15 cm. Construct triangle ABC. Draw the perpendicular
bisector of all three sides. What do you observe?

Answers

Answered by amritasingh2323
3

Step-by-step explanation:

. Draw a line AB of 15 cm.

2. At point A draw an angle CAB of 600

3. At point B draw an angle DBA of 600

4. Draw the angle bisector of ∠CAB and ∠DBA, both the angle bisector intersect each other at P.

5. Draw the perpendicular bisector of AP and BP, it intesect AB at Q and R respectively.

6. Join PQ and PR.

Hence ΔPQR is the required triangle.

Answered by pratham7777775
8

Answer:

Steps of construction:

Steps of construction:(1) Draw a sufficiently long line segment using a ruler.(2) Locate points A and B on it such that AB = 5 cm.(3) With A as the centre and radius 3.7 cm, draw an arc.(4) With B as the centre and radius 4.6 cm, draw another arc that cuts the previous arc at C.(5) Join AC and BC.Then, ABC is the required triangle.

I hope it helps you ✌️

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