The perimeter of the floor of a rectangle room is 17 m and its lenght is 5 m. The cost of flooring the room with square tiles of side 25 cm at the rate of rupee 850 per 100 tiles
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Question :-
The perimeter of the floor of a rectangle room is 17 m and its lenght is 5 m. Find the cost of flooring the room with square tiles of side 25 cm at the rate of rupee 850 per 100 tiles.
Answer :-
Floor Dimensions -
- perimeter , p = 17 m = 1700 cm
- length , l = 5 m = 500 cm
- breadth , b = (p - 2l)/2 = (17 - 10)/2 = 3.5 m = 350 cm
Tile Dimensions -
- side , a = 25 cm
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Thus,
area of floor
= l × b
= 500 cm × 350 cm
= 105000 cm²
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Now,
area of each tile
= a²
= ( 25 cm )²
= 625 cm²
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Henceforth,
No. of Tiles required
= (area of floor) ÷ (area of 1 tile)
= (105000) ÷ (625)
= 4200 / 25
= 168 tiles
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Hence, the number of tiles required are 168 tiles.
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.... Thank You !!
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