Question

The perimeter of the floor of a rectangular hall is 300m. It's height is 8m . Find the area of the four walls of the room

Answer 1

Perimeter of floor = 300 m

=> 2(L+B) = 300

Height = 8 m

Area of four walls = 2(L+B) * H

= 300 * 8

= 2400 cm^2

Answer 2

perimeter of rectangle = 2(l+b) = 300m 
Thus, curved surface area of cuboid = 2(l+b)h
                                                              = 300*8
                                                              = 2400m²