the perimeter of the floor of a rectangular room is 17 metre and its length is 5 metre find first the breadth of the room then the floor area of the room then the cost of the floor in the room in the square tiles of side 25 cm @ rupees 850 per hundred tiles.
Answers
Answer:
rupees 2380
Step-by-step explanation:
The perimeter of rectangle = 2(length+breadth)
The perimeter of floor of rectangular room = 17 m
The length of the romm= 5 m
so
2(5m+breadth) = 17m
10m + 2 breadth = 17m
2breadth = 17m-10m
2breadth. = 7m
breadth. = 7/2 m = 3.5 m
Area of room floor. = length × breadth
so area of room floor. = 5m × 3.5 m
= 17.5 sq m
1m. =100cm
area of room floor (in cm) = 17.5×100×100= 175000 sq cm
The side of sq. tile. = 25 cm
the area of sq. tile. = side × side
the area of sq. tile. = 25 cm × 25 cm = 625 sq cm
total no. of tiles required. = area of floor/ area of tile
= 175000 sq cm/ 625 sq cm
= 280 tiles
cost of tiles. = 850 rs per 100
so total cost of 280 tiles. = 280/100×850rs
=2380 rs