the perimeter of the floor of a room is 40m and its height is 4.5m find the area of four walls of the room
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We are given perimeter of floor = 40 m
We know that floor is in the shape of rectangle
so, 2(l+b) = 40
so, (l+b) = 20 m ................................................................(1)
we also have, height, h = 4.5 m
So, Area of four walls = 2(l+b)h
= 2(l+b)*4.5
= 2(20)*4.5 [By Eqn (1)]
= 20*9
= 180 m²
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We know that floor is in the shape of rectangle
so, 2(l+b) = 40
so, (l+b) = 20 m ................................................................(1)
we also have, height, h = 4.5 m
So, Area of four walls = 2(l+b)h
= 2(l+b)*4.5
= 2(20)*4.5 [By Eqn (1)]
= 20*9
= 180 m²
Plz Mark as brainliest
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