Question

The perimeter of the floor of a room is 40m and its height is 3.5m .Find the area of the four walls of the room .Also find the cost of papering the four walls at rupees35 per metre square

Answer 1

Answer:

Area of four walls =LSA=perimeter*height=40*3.5=140 m²

cost of papering the walls=140*35=4900 Rs.

Answer 2

Given:- Perimeter of the rectangular floor:-40m

Height of the room:-4m

To find:- Area of the four walls or CSA of the room.

Solution:- We know that the CSA of a cuboid:- 2h(l+b)

or:- hx2(l+b)

Also, 2(l+b)= Perimeter of the rectangle. So,

CSA of Room:- hx40

:- 4x40

:- 160m^2#KEEPLEARNING

HOPE I AM CLEAR.

WARM REGARDS.

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