the perimeter of the floor of a room is 46m and it's height is 3.5m. find the area of the walls of the room
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Given that Perimeter= 46m
We know that Perimeter= 2(l+b)
Area of the four walls of the room= LH+BH+LH+BH= 2LH+2BH= 2H(L+B)= 2(L+B) × H
Height= 3.5m
By Substituting the value of 2(L+B) in the Area of the walls we get,
Perimeter of floor × height= 46 × 3.5= 161m2
We know that Perimeter= 2(l+b)
Area of the four walls of the room= LH+BH+LH+BH= 2LH+2BH= 2H(L+B)= 2(L+B) × H
Height= 3.5m
By Substituting the value of 2(L+B) in the Area of the walls we get,
Perimeter of floor × height= 46 × 3.5= 161m2
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