the perimeter of the floor of the room is 46 M and its height is 3.5 M find the area of the Wall of the room
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given , 2 (l+b)=46
area of walls = 2 (l+b) h
46×3.5
161m^2
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Area of wall =2[l×h+b×h]
=2h[l+b]
=h[2(l+b)]
=h× perimeter of floor
=3.5×46=161m²
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