Question

The perimeter of the floor of the room is 46m and its height is 3.5 m . Find the area of the walls of the room .​

Answer 1

Answer:

The area of the of the walls of the room is "161 m^{2}m

2

".

Step-by-step explanation:

Given,

The perimeter of the floor of a room = 46 m and

The height(h) = 3.5 m.

To find, the area of the of the walls of the room = ?

We know that,

The perimeter of rectangular room = 2(l+b)

Where, l = length and b =breadth

∴ 2(l+b) = 46 ....(1)

The area of the of the walls of the room = 2(l + b) × h

= 46 × 3.5 m^{2}m

2

= 161 m^{2}m

2

Hence, the area of the of the walls of the room is "161 m^{2}m

2

Answer 2

Answer:

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