Question

The perimeter of the front wheel of an engine is 1 m 4
dcm. and the perimeter of its hind wheel is two and half
times more than the front wheel. Let's find, the least
distance coveres by the wheels, when they will simulta-
neously take exact number of complete revolutions?​

Answer 1

Step-by-step explanation:

Answer:

Perimeter of the back wheel = 9 feet, front wheel = 7 feet on a certain distance, the front wheel gets 10 revolutions more than the back wheel What is the distance?

7(f+10) = 9f

7f+70 = 9f

f = 35 revolutions of the front wheel distance = 35*9= 315 feet

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Answer 2

Step-by-step explanation:

Given diameter of front wheels(2r)=80cm⇒r=40cm

diameter of rear wheels(2r)=2m⇒r=1m=100cm

In one revolution area covered is =2πr

∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)

Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)

As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)

x=

100

1400×40

=560

That means rear wheel will make 560 revolutions to cover the required distance.