Question

The perimeter of the given ABC is 41.36 cm. Find the area
of ABC.​

Answer 1

Answer:

81.8sqcm

Step-by-step explanation:

the remaining side bc of the given triangle is bc = 41.36-10-15 =16.36

since AC is hypotenuse of the given triangle the sides ab and bc is the height and base of it

so area of the triangle = 1/2*base*height

1/2*16.36*10 = $81^{2} cm$

HOPE IT HELPS