The perimeter of the given triangle ABC is 41.36cm. Find the area of triangle ABC
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Area of triangle=1/2×Base×Height Area of triangle = √[s ( s − a )( s − b )( s − c )],
Here a , b and c are sides of triangle
And 2s = a + b + c
Given that perimeter of triangle and also have no information about the nature of triangle .
If the triangle is equilateral triangle , and then perimeter = 41.36 cm than find area of this triangle , Sides of equilateral triangle = 41.363 / 3 = 13.78 cm And Area of equilateral triangle = √3/4×(Side)2 ,
So Area of equilateral triangle = √3/4×(13.78)2 = 82.22 cm2
Here a , b and c are sides of triangle
And 2s = a + b + c
Given that perimeter of triangle and also have no information about the nature of triangle .
If the triangle is equilateral triangle , and then perimeter = 41.36 cm than find area of this triangle , Sides of equilateral triangle = 41.363 / 3 = 13.78 cm And Area of equilateral triangle = √3/4×(Side)2 ,
So Area of equilateral triangle = √3/4×(13.78)2 = 82.22 cm2
vivek4569:
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