the perimeter of the Isoleces triangle is 32. the ratio of the equal side to its base is 3:2 find the area of the triangle
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Given:
- Perimeter of isosceles triangle is 32 cm.
- Ratio of equal sides to base = 3 : 2
To Find:
- Area of triangle
Solution:
Let the equal side = 3x
So, base = 2x
★ Perimeter of the triangle = 32
⇒ 3x + 3x + 2x = 32
⇒ 8x = 32
⇒ x = 4.
Then,
- Equal side = 3x = 3×4 = 12
- Base = 2x = 2×4 = 8
The sides of the triangle = 12cm, 12cm and 8cm.
Let a = 12, b = 12, c = 8
★ s = (a + b + c)/2
→ s = (12 + 12 + 8)/2
→ 32/2
→ 16.
★Area of the triangle = √s(s - a)(s - b)(s - c)
→ √16(16 - 12)(16 - 12)(16 - 8)
→ √16 × 4 × 4 × 8
→ 32√2 cm²
Hence,
- Area of triangle = 32√2cm²
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