Question

The perimeter of the isosceles triangle is 28cm. when both side are 4y and (6y-2x+1) and base is (x+2y).find x and y and hence state the length of the side of the triangle

Answer 1

Answer:

x=3. y=5/2

Step-by-step explanation:

the perimeter of triangle is sum of all side

that is 4y+(6y-2x+1)+(x+2y)=28

12y-x+1=28 eqs --1

as the base is x+2y the other two side are eqaul as the triangle is isosceles so we have

4y=6y-2x+1

2y-2x+1=0. eqs--2

from eqs 1 and 2 we solve the fromula

multiple 2 in equation 1 and solving

24y-2x+2=56

2y-2x+1=0

sub the eqs we get

22y+1=56

22y=55

y=55/22=5/2

now put the value of y in eqs 2

5-2x+1=0

6=2x

x=3