The perimeter of the quadeant of
circle is 25cm find its area
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Answer:
Let the radius of the circle be r
Now, perimeter of quadrant
=1/4(2πr) +2r
=25=1/2×22/7×r+2r
25=25r/7
r=7cm
Area of quadrant
1/4πr^=1/4×22/7×7×7
hence, the area of quadrant is 38.5cm^
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