Question

The perimeter of the rectangle and square are same .Length and breadth of
the rectangle are 10 cm and 8 cm respectively. What is the area of the
square.

Answer 1

$\huge \bf \purple{Hey \: there !! }$


➡ Given :-

→ Length of rectangle ( l ) = 10 cm.

→ Breadth of rectangle ( b ) = 8 cm.

→ Perimeter of rectangle = Perimeter of square.


➡ To find :-

→ Area of square.


▶ Solution :-

°•° Perimeter of rectangle = 2 ( l + b ) .

= 2 ( 10 + 8 ) .

= 2 × 18 .

= 36 cm.


▶Now,

→ Perimeter of rectangle = perimeter of square.

°•° Perimeter of square = 4 × side .

=> 36 = 4 × side .

=> Side = 36/4 .

•°• Side = 9 cm .


▶ Now,

°•° Area of square = Side × Side .

= 9 × 9 .

$\huge \pink{ \boxed{ \boxed{ = 81 {cm}^{2} \: .}}}$


✔✔ Hence, it is solved ✅✅.

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$\huge \green{ \boxed{ \boxed{ \boxed{ \mathbb{THANKS}}}}}$



$\huge \bf \blue{ \#BeBrainly.}$

Answer 2

Given:

Dimensions of rectangle = 10 cm and 8 cm

And the perimeter of the rectangle and square are equal.

To Find :

Area of the square.

Solution :

Perimeter of the rectangle = 2(Length+Breadth)

= 2(10+8) = 2(18) = 36 cm

Now it is given that the perimeter of the rectangle and square are equal so ,

4(Side) = 36 cm

Side = 36/4 = 9 cm.

Then,

Area of the square =

Side² = 9² = 9×9 = 81 cm² .

${ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{ { \red{\huge{81 \: {cm}^{2} }}}}}}}}}}}}}$

★ AhseFurieux ★