the perimeter of the rectangle is 130cm. if the length of the rectangle is 10cm less than twice of its breadth, find the number of the rectangle. by equation coefficient method
Answers
Answered by
1
Perimeter of rectangle=130cm
⇒2(length+breadth)=130cm
⇒2(length+30)=130
⇒ length+30=
2
130
⇒ length+30=65
⇒ length=65−30=35cm
Now area of rectangle=length×breadth=35×30=1050cm
2
Thus, the area of rectangle is 1050cm
2
.
⇒2(length+breadth)=130cm
⇒2(length+30)=130
⇒ length+30=
2
130
⇒ length+30=65
⇒ length=65−30=35cm
Now area of rectangle=length×breadth=35×30=1050cm
2
Thus, the area of rectangle is 1050cm
2
.
Answered by
0
Step-by-step explanation:
Perimeter of rectangle=130cm
⇒2(length+breadth)=130cm
⇒2(length+30)=130
⇒ length+30=
2
130
⇒ length+30=65
⇒ length=65−30=35cm
Now area of rectangle=length×breadth=35×30=1050cm
2
Thus, the area of rectangle is 1050cm
2
Similar questions
Math,
23 days ago
Computer Science,
1 month ago
Social Sciences,
1 month ago
Hindi,
8 months ago
English,
8 months ago