the perimeter of the rectangle is 232 m. the width is 36 m. what is the length of the rectangle?
Answers
Answered by
2
Let the length of the rectangle be l and breadth/width = 36 m
then,
perimeter of rectangle = 2(l+b)
→ 232 = 2(l+36)
→ 232 = 2l+72
→ 232-72 = 2l
→ 2l = 160
→ l = 160/2
→ l = 80
Hence length of the rectangle is 80 m
then,
perimeter of rectangle = 2(l+b)
→ 232 = 2(l+36)
→ 232 = 2l+72
→ 232-72 = 2l
→ 2l = 160
→ l = 160/2
→ l = 80
Hence length of the rectangle is 80 m
Answered by
2
p =2(l+w)
232=2(l+36)
116=l+36
l=116-36
l=80m
232=2(l+36)
116=l+36
l=116-36
l=80m
Similar questions