the perimeter of the rectangle is 40 metre if the side of rectangle are natural numbers find the dimension of rectangle having the maximum area
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Answer:
Perimeter of rectangle =40 cm (given)
condition :- length = 2× breadth +2
⇒l=2b+2
perimeter p=2(l+b)=40
⇒2(2b+2+b)=40
⇒2(3b+2)=40
⇒6b=40−4=36
∴b=6cm
l=2×6+2=12+2=14cm
∴ length =14 cm, breadth =6 cm
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