The perimeter of the rectangle is 40cm and it's area is 96 sq cm. calculate its length and breadth.
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Let the length and breadth of the rectangle be L and B.
2(L+B) = 40, or
L + B = 20, or
B = 20-L …(1)
LB = 96 …(2). Put value of B from (1) in (2), to get
L(20-L) = 96, or
20L - L^2 = 96, or
L^2–20L+96 = 0
(L-12)(L-8) = 0, or
L = 12 or 8 (not acceptable), while B = 8 or 12 (not acceptable)
Length is 12 cm and breadth is 8 cm.
2(L+B) = 40, or
L + B = 20, or
B = 20-L …(1)
LB = 96 …(2). Put value of B from (1) in (2), to get
L(20-L) = 96, or
20L - L^2 = 96, or
L^2–20L+96 = 0
(L-12)(L-8) = 0, or
L = 12 or 8 (not acceptable), while B = 8 or 12 (not acceptable)
Length is 12 cm and breadth is 8 cm.
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