The perimeter of the rectangle is 52cm where the length is 6cm more than the width of rectangle from the pair of linear equation find the dimensions of rectangle
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Hey friend here is your answer
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Perimeter of rectangle is 52cm
Length is 6cm
Breadth =?
Let breadth be x
Perimeter of rectangle = 2 (l+b)
52 = 2 (6+x)
52=12 + 2x
52 - 12=2x
40 = 2x
40÷2 = x
20= x
therefore width of rectangle is 20cm
The dimensions of rectangle are
6cm , 20cm, 6cm, 20cm
_________________________
Hope it will help you friend.
_______________________
Perimeter of rectangle is 52cm
Length is 6cm
Breadth =?
Let breadth be x
Perimeter of rectangle = 2 (l+b)
52 = 2 (6+x)
52=12 + 2x
52 - 12=2x
40 = 2x
40÷2 = x
20= x
therefore width of rectangle is 20cm
The dimensions of rectangle are
6cm , 20cm, 6cm, 20cm
_________________________
Hope it will help you friend.
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