Question

The perimeter of the rectangle is 80 cm.
The area of the rectangle is A cm2.
(i) Show that x2 – 40x + A = 0.

Answer 1

Answer:

ANSWER

Perimeter of rectangle = perimeter of square =80 cm

⇒2(l+b)=45=80

⇒S=

4

80

=20 cm;2(l+b)=80

⇒l+b=40 cm - (1)

difference m areas = 100 cm

2

5

2

−(lb)=100

(20)(20)−(lb)=100

⇒lb=300 - (2)

From (1) and (2)

30+10=40;3×10=l×b

⇒l=30 and b=10

sides of rectangle are 30,10 cm

Answer 2

Answer:

Perimeter of rectangle = perimeter of square =80 cm

⇒2(l+b)=45=80

⇒S=

4

80

=20 cm;2(l+b)=80

⇒l+b=40 cm - (1)

difference m areas = 100 cm

2

5

2

−(lb)=100

(20)(20)−(lb)=100

⇒lb=300 - (2)

From (1) and (2)

30+10=40;3×10=l×b

⇒l=30 and b=10

sides of rectangle are 30,10 cm

Step-by-step explanation:

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