The perimeter of the rectangle whose length is 60 cm and a diagonal is 61 cm is
A) 120cm
B) 122cm
C)71cm
D) 142cm
Answers
Answered by
29
Answer:
d)142 cm
Step-by-step explanation:
L=60cm
D=61cm
As we know Pythagoras theorem
P²+b²=h²
=>l²+B²=D²
=>60²+b²=61²
=>3600+b²=3721
=>B²=3721-3600
=>b²=√121
=>b=11
P=2(l+b)
=>P=2(60+11)cm
=>P=2*71 cm
=>P=142 cm
Mark as brainliest answer.
Answered by
10
Answer:
D) 142cm.
Step-by-step explanation:
Let ΔBCD be the given rectangle such that
AB = CD = 60 cm and AC = 61 cm.
In ΔABC, (AC)2 = (AB)2 + (BC)2 ⇒ (61)2
= (60)2 + (BC)2 ⇒ (BC)2 = 3721 – 3600
= 121 = 112 ⇒ BC = 11 cm
∴ Perimeter of rectangle ABCD = 2(AB + BC) = 2 (60 + 11) = 2(71) = 142
hope it helps =D
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