The perimeter of the rectangular field 82m and the area of its 400msq.Find the length and breadth
Answers
Answered by
1
l*b= 82 m
perimeter= 2*(l+b)
let the length be x
let the breadth be y
then,
x*y= 82
x= 82/y
then,
2*(x+y)= 400
2*(82/y+y)= 400
perimeter= 2*(l+b)
let the length be x
let the breadth be y
then,
x*y= 82
x= 82/y
then,
2*(x+y)= 400
2*(82/y+y)= 400
Answered by
0
Answer:
breadth = 16
Step-by-step explanation:
given
perimeter of the rectangle = 82 metres
area of the rectangle = 400 metres²
perimeter of rectangle = 2 (length+breadth)
82 = 2(l+b)
41 = l+b----------(1)
area of rectangle = length × breadth
400 = l×b-------(2)
=(41-b)×b = 400
41b - b² = 400
b²-41b+400 = 0
solving this
breadth = 16
length = 25
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