Question

The perimeter of the rectangular garden is 180 meters.If the length of the garden is 10 meters more than is width ,What wil be the area of the garden

Answer 1

Answer:

$\bigstar{\bold{Area\:=\:2000\:m^{2} }}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Perimeter of rectangular garden = 180 m
• Length of garden is 10 m more than width

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Area of the garden

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Let length be l and breadth be b

→ By given data

  l = b + 10

→ Peimeter of a rectangle = 2( l + b )

  which is give as 180 m

→ Substituting the value of l we get

  2 ( b+ 10 +b ) = 180

 4b + 20 = 180

  4b = 160

    b = 40 m

→ l = b+ 10 = 40 + 10 = 50 m

→ Area of rectangle = l × b

  Area = 40 × 50 = 2000 m²

$\boxed{\bold{Area\:=\:2000\:m^{2} }}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ Perimeter of a rectangle = 2(l + b)

→ Area of a rectangle = l × b

where l is the length and b is the breadth of the rectangle

Answer 2

$\huge\underline\bold{QUESTION:-}$

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The perimeter of the rectangular garden is 180 meters. If the length of the garden is 10 meters more than the width What will be the area of the garden

__________________________________________

$\huge\underline\bold{TO FIND:-}$

__________________________________________

The area of the rectangle if the length exceeds the breadth by 10 and the perimeter is 180 meters

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$\huge\underline\bold{SOLUTION:-}$

$\rightarrow$ Perimeter of the rectangle= 180ms

$\rightarrow$ Let the breadth of rectangle= x ms

$\rightarrow$ Length of the rectangle= x+10 ms

Perimeter= Sum of all these sides

180 ms= 2(x+x+10)

180 ms= 4x+20

4x= 160 ms

x=40 ms

★ Breadth of the rectangle = 40 ms

★ Length of rectangle= x+10 = 40+10=50 ms

$\huge\underline\bold{ANSWER:-}$

_________________________________

★ Area = Length × breadth

★ Area = 40×50 ms²

★ Area =2000ms²