The perimeter of the Rhombus is 144 CM one of the diagonal is 48 cm fine area of the Rhombus
Answers
Answered by
1
Step-by-step explanation:
Perimeter of a rhombus = 4a
4a = 144 => a = 144/4 => a = 36
Area of rhombus when diagonals are known = d¹ * d² *1/2
From the above attachment d² = 53.6
area = 48 × 53.6 × 1/2
= 1286.4 cm²
Hope this answer is helpful my friend Please please mark my answer as brainlist if you are satisfied
Thank you
Attachments:
Similar questions