Math, asked by harsita44, 10 months ago

the perimeter of the Rhombus is 20 cmand length of one diagonal is 8 cm. then the length other diagonal is

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Answered by aryan4025

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Answered by Anonymous

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perimeter of the Rhombus=20 cm

therefore side of the Rhombus=(20/4)cm=5 cm

now ....half of diagonal AC is =OC=(1/2)8=4 cm

now we know that the diagonals of a Rhombus bisect each other at right angle so....

$\implies CD {}^{2} =OC {}^{2} +OD {}^{2} \\ \implies OD = \sqrt{CD {}^{2} - OC {}^{2}} \\ \implies OD = \sqrt{5 {}^{2} - 4 {}^{2} } = 3 \: cm$

therefore length of the other diagonal is

=2×3cm=6cm

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the perimeter of the Rhombus is 20 cmand length of one diagonal is 8 cm. then the length other diagonal is​

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the perimeter of the Rhombus is 20 cmand length of one diagonal is 8 cm. then the length other diagonal is