Question

the perimeter of the Rhombus is 328 CM one of the diagonal is 160 cm find the length of the Other diagonal and area of Rhombus

Answer 1

$328 \div 4 = 82cm \\ diagonal = 2( \sqrt{ {82}^{2} - {80}^{2}) } \\ = 2( \sqrt{6724 - 6400)} \\ = 2 \times 18 \\ = 36cm$