the perimeter of the sector of the circle of area 64n sq.cm is 56cm.find the area of sector is
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Answer:
Given : perimeter=πr
2
=64π⇒r=8
Length of the Sector =56=2πr∗
360
θ
⇒
360
θ
=
π16
56
Now Area of Sector =
360
θ
∗64π=
π16
56
∗64π=56∗4=224 sq cm
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