Question

. The perimeter of the sector whose radius is 14cm and angle at the centre 45° then
(WITH THE FULL SOLUTION PLEASE)​

Answer 1

☯︎ Given :-

• Radius = 14cm
• angle = 45°

☯︎ To Find :-

• Perimeter of sector

☯︎ Solution :-

Radius = 14cm

Angle at centre = 45°

Perimeter of sector = $\dfrac{\theta}{360°}\times2πr$

= $\dfrac{45°}{360°}\times2\times\dfrac{22}{7}\times14$

= $\dfrac{1}{8}\times2\times\dfrac{22}{\cancel{7}}\times{\cancel{14}}$

= $\dfrac{2\times22\times2}{8}$

= $\dfrac{88}{8}$

= $\large{\purple{\underline{\red{\boxed{\color{lime}{Perimeter\:=\:11\:cm}}}}}}$