Question

The perimeter of the squares are 12 cm, 16 cm and 10 cm respectively. find the side of a square whose are is equat to the sum of the areas of first two squares​

Answer 1

Solution!!

The perimeters of some squares are given. There is another square whose area is equal to the sum of the areas of the first two squares.

Perimeter₁ = 12 cm

Perimeter₁ = 4 × Side₁

12 cm = 4 × Side₁

Side₁ = 12 cm ÷ 4

Side₁ = 3 cm

Area₁ = (Side₁)²

Area₁ = (3 cm)²

Area₁ = 9 cm²

Perimeter₂ = 16 cm

Perimeter₂ = 4 × Side₂

16 cm = 4 × Side₂

Side₂ = 16 cm ÷ 4

Side₂ = 4 cm

Area₂ = (Side₂)²

Area₂ = (4 cm)²

Area₂ = 16 cm²

Area₁ + Area₂ = Area₃

9 cm² + 16 cm² = Area₃

Area₃ = 25 cm²

Area₃ = (Side₃)²

25 cm² = (Side₃)²

Side₃ = √25 cm²

Side₃ = 5 cm