The perimeter of the squares are 12 cm, 16 cm and 10 cm respectively. find the side of a square whose are is equat to the sum of the areas of first two squares. please answer fast and step by step
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Step-by-step explanation:
Perimeter of first square = 12 cm.
Therefor, Its side = 124=3 cm
Therefore, Its area = 32=9 sq.cm.
Perimeter of second square = 16 cm
Therefore, Its side = 164=4 cm
Therefore, Its area = 42=16 sq.cm.
Therefore, Area of new square = 9 + 16 = 25 sq. cm
Its side =
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