Question

The perimeter of the squares are 12 cm, 16 cm and 10 cm respectively. find the side of a square whose are is equat to the sum of the areas of first two squares. please answer fast and step by step​

Answer 1

Step-by-step explanation:

Perimeter of first square = 12 cm.

Therefor, Its side = 124=3 cm

Therefore, Its area = 32=9 sq.cm.

Perimeter of second square = 16 cm

Therefore, Its side = 164=4 cm

Therefore, Its area = 42=16 sq.cm.

Therefore, Area of new square = 9 + 16 = 25 sq. cm

Its side =