the perimeter of the three squares are 360 CM 240 cm and 80 CM the diagonal of a square which is equal in the area to these three is
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side of first square = 360/4 = 90 cm
side of second square = 240/4 = 60cm
side of third square = 80/4= 20 cm
area of first square = 90*90 = 8100 cm ^2
area of second square = 60*60 = 3600 cm ^2
area of third square = 20*20 = 400 cm ^2
total area = 12100 cm ^ 2
let the side of this square is x then x^ 2 = 12100
use phythagus theorm
x^2 + x^2 = (diagonal)^2
2 * X ^2 = (diagonal)^2
2* 12100= ( diagonal )^2
24200 =(diagonal )^2
diagonal = √ 24200 = 155.56 cm
side of second square = 240/4 = 60cm
side of third square = 80/4= 20 cm
area of first square = 90*90 = 8100 cm ^2
area of second square = 60*60 = 3600 cm ^2
area of third square = 20*20 = 400 cm ^2
total area = 12100 cm ^ 2
let the side of this square is x then x^ 2 = 12100
use phythagus theorm
x^2 + x^2 = (diagonal)^2
2 * X ^2 = (diagonal)^2
2* 12100= ( diagonal )^2
24200 =(diagonal )^2
diagonal = √ 24200 = 155.56 cm
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