Question

the perimeter of the triangle ABC is 41.36cm .find the area of triangle ABC​

Answer 1

Answer:

The remaining side bc of the given triangle is bc = 41.36-10-15 =16.36

since AC is hypotenuse of the given triangle the sides ab and bc is the height and base of it

so area of the triangle = 1/2*base*height

1/2*16.36*10 = 81.8sqcm