Question

The perimeter of the triangle formed by the points (-a, 0),(a,0) and (0,a) is
A) 2a(1+√2)
B) a (2+√2)
c)2(a+√ 2)
D) none​

Answer 1

Answer:

option A

$2a(1 + \sqrt{2)}$

Step-by-step explanation:

Let triangle be ABC , A(-a,0) B(a,0) and C(0,a)

Find distance between AB using distance formula

$\sqrt{ {(x1 - x2)}^{} {}^{2} + {(y1 - y2)}^{2} }$

we get AB = 2a

BC = √2a

AC = √2a

Perimeter of triangle = AB + BC + CD

= 2a + √2a + √2a

= 2a + 2√2a

= 2a(1+ √2)