The perimeter of the triangle is 154 cm . if it's sides are in the ratio 9 :7:6 find its area
Answers
Given:
- The perimeter of the triangle is 154 cm.
- It's sides are in the ratio 9:7:6.
To find:
- The area of a triangle.
Solution:
Let,
a = 9x
b = 7x
c = 6x
- Perimeter of a triangle = a + b + c
- 154 = 9x + 7x + 6x
- 154 = 22x
- x = 154/22
- x = 77
Now,
⟹ a = 9 × 77
⟹ a = 693 cm
⟹ b = 7 × 77
⟹ b = 539 cm
⟹ c = 6 × 77
⟹ c = 462 cm
Now, find Semi-perimeter, S
- S = ( a + b + c )/2
- S = (693 + 539 + 462)/2
- S = 1694/2
- S = 847
- Area of triangle = √s(s - a ) ( s - b ) ( s - c )
- Area of triangle = √847( 847 - 693 ) ( 847 - 539 ) ( 847 - 462 )
- Area of triangle = √847 × 154 × 308 × 385
- Area of triangle = √7 × 11² × 2 × 7 × 11 × 2² × 7 × 11 × 5 × 7 × 11
- Area of triangle = √7² × 11² × 2 × 11² × 2² × 7² × 5 × 11
- Area of triangle = (7 × 11 × 11 × 2 × 7)√2 × 11 × 5
- Area of triangle = 11858√110
- Area of triangle = 11858√110 cm²
∴ The area of a triangle = 11858√110 cm²
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Answer:
- Area of Triangle is 1027.83cm²
Step-by-step explanation:
Given :
- Perimeter of Triangle = 154cm
- Ratio of its sides = 9:7:6
To Find :
- Area of Triangle
Solution :
Let,
- First Side of Triangle = 9b
- Second Side of Triangle = 7b
- Third Side of Triangle = 6b
According to the Question :
⠀⟶⠀Perimeter = Sum of all Sides
⠀⟶⠀154 = 9b + 7b + 6b
⠀⟶⠀154 = 9b + 13b
⠀⟶⠀154 = 22b
⠀⟶⠀154/22 = b
⠀⟶⠀7 = b
Therefore :
- First Side = 9b
- First Side = 9 × 7
- First Side = 63cm
- Second Side = 7b
- Second Side = 7 × 7
- Second Side = 49cm
- Third Side = 6b
- Third Side = 6 × 7
- Third Side = 42cm
Now finding the semi perimeter :
⠀⟶⠀Semi Perimeter = a + b + c/2
⠀⟶⠀Semi Perimeter = 63 + 49 + 42/2
⠀⟶⠀Semi Perimeter = 63 + 91/2
⠀⟶⠀Semi Perimeter = 154/2
⠀⟶⠀Semi Perimeter = 77cm
Now applying Heron's Formula :
⠀⟶⠀Area = √s (s - a) (s - b) (s - c)
⠀⟶⠀Area = √77(77 - 63)(77 - 49)(77 - 42)
⠀⟶⠀Area = √77 × 14 × 28 × 35
⠀⟶⠀Area = √1078 × 980
⠀⟶⠀Area = √10,56,440
⠀⟶⠀Area = 1027.83cm²
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