the perimeter of the triangle is 54cm and it's sides are in the ratio 5 ratio 6 ratio 7 • find the area of the triangle
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Answer:
given ,
perimeter of the triangle = 54 cm
let the sides be 5x , 6x and 7x
therefore perimeter of the triangle= sum of sides
= 54 = 5x + 6x +7x
= 54 = 18 x
= x = 54/18
= x = 3
put x = 3 in 5x ,6x ,7x
5x = 5 × 3 = 15
6x = 6 × 3 = 18
7x = 7 × 3 = 21
Now , semi perimeter = 54/ 2 = 27
let a = 15
b= 18
c= 21
Area of the triangle = √ s (s-a) (s-b) (s-c)
= √27 (27- 15) (27-18) (27-21)
= √27 × 12 × 9 × 6
= √ 17,496
= 132.27
hope it helped
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