Math, asked by advaitamadduluri, 1 month ago

The perimeter of the triangle whose vertices are (-1, 4)(-4,-2), (3, -4) will be:please answer this question and I'll mark them the brainliest​

Answers

Answered by ᏢerfectlyShine
3

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Answered by GraceS
2

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HERE IS UR ANSWER

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We know that the distance between the two points (x1,y1) and (x2,y2) is 

d= \sqrt{} (x2−x1) {}^{2} +(y2−y1) {}^{2}

Let the given vertices be A=(−2,1), B=(4,6) and C=(6,−3)

We first find the distance between A=(−2,1) and B=(4,6) as follows:

AB=

 \sqrt{} (x2−x1) {}^{2} +(y2−y1)2 {}^{2}  \\ = \sqrt{} (4−(−2)) {}^{2} +(6−1) {}^{2} </p><p>     = \sqrt{} (4+2) {}^{2} +52 {}^{2} =  \sqrt{?} {6}^{2} +  {5}^{2}  = \sqrt{} 36+25 =  \sqrt{61} </p><p>

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