Question

The perimeter of the two squares are the 192 cm and 56 cm find the perimeter of the square whose area is equal to the sum of the area of the these two spuares.

in the use the formula

Answer 1

Length of a side of square having perimeter 192 = 192/4 = 48 cm

Similarly, length of side of square with perimeter 56 = 56/4 = 14 cm
Since area of a square = (side)^2,
Total area of both squares = 48^2 + 14^2
= 2500cm^2
Let side of square whose perimeter is to be found be x cm
Then, according to given question
x^2 = 2500
X = 50 cm
Therefore, it's perimeter is equal to 50*4 = 200cm

Answer 2

Answer:

820

Step-by-step explanation:

PERIMETER OF THE SQ=728CM AND 336 CM SQ

PERIMETER OF SQ= 4a

4a=784

a=784/4

a=187

AREA OF SQ=A*A

                     =187*187

                     =34969

4a=336

a=336/4

a=84

a*a=84*84

a=7056

sum of the area=34969+7056

                            =42025

side of the area=sq root of 42025

                         =205

perimeter of new square=4*205

                                         = 820