Question

the perimeter of this isosceles trapezium is 92 cm .Find the value of *

Answer 1

peimeter of an isosceles trapezium =a+b+c+d.

: x+x+x+2+x+10= 92

: x=20.

Answer 2

Hey mates. ........

Perimeter = Sum of all sides

so , A/q

Perimeter of trapezium = a+b+c+d

so , = x+x+2+x+x+10 = 92

= 4x= 92 - 12

= 4x = 80

= x =

$\frac{80}{4}$

x = 20. Answer ...

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