the perimeter of trapezium is 120 m if bc = 48 m, cd = 17 m and ad=40 m find the area of this field. it is given that side ab is perpendicular to parallel sides ad and bc .
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2
1/2(48 sum40) *4
196m2
196m2
Rudrankshi:
the answer is 660 sq.m
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17
p=sum of all side=120
let fourth side be x
48+40+17+x=120
x=an=120-105=15m
area of trapezium=1÷2(sum of || side) ×h
=1÷2×88×15
= 660 m square
let fourth side be x
48+40+17+x=120
x=an=120-105=15m
area of trapezium=1÷2(sum of || side) ×h
=1÷2×88×15
= 660 m square
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