The perimeter of trapezium is 150m . If BC =60 m, CD=25 m, AD = 50m , find the area of the trapezium ABCD. It is given that side AB is perpendicular to the parallel sides AD and BC.
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Length of the fence of trapezium ABCB = 150m. BC= 60m, CD = 25m and AD = 50m.
Length of the fence of a trapezium ABCD
= AB + BC + CD + AD
150= AB + 60 + 25 + 56
150 = AB + 135
150 - 135 = AB
AB = 15m
Height ( AB) = 15m
Area of trapezium = 1/2 × sum of parallel sides × perpendicular distance
Area of trapezium = 1/2 × (60+50)×15
= 1/2 × 110 × 15
= 55 × 15
= 825m²
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