Question

The perimeter of triangle 6x²-4x+9 and two of its sides are x²-2x+1 and 3x²-5x+3. Find the third side of triangle.​

Answer 1

Answer:

Measure Of Third Side :-

(x² + 3x - 5)

Step-by-step explanation:

Let the Third Side Be = 'q'

$({x}^{2} - 2x + 1) + ( {3x}^{2} - 5x + 3) + (q) = 6 {x}^{2} - 4x + 9 \\ = ) {4x}^{2} - 7x + 4 + (q) = {6x}^{2} - 4x + 9 \\ = )q = {6x}^{2} - 4x + 9 - (4 {x}^{2} - 7x + 4) \\ = ) {6x}^{2} - 4x + 9 - {4x}^{2} + 7x - 4 \\ = ) {2x}^{2} + 3x - 5$

Hope it helped

Answer 2

Refer to the attached image ☺️