Question

The perimeter of triangle ABC is 50 cm . Its sides AB, BC and and AC are respectively 15 cm,10 cm and (x +4) Cm.Find the value of x.

Answer 1

since the perimeter of triangle is given by
sum of sides of the given triangle ...
then ,,,,
X + 4 +15 + 10 = 50
x = 50-29
= 21.,
x = 21

Answer 2

perimeter of a triangle = sum of all its sides
50=15+10+4+x
50=29+x
50-29=x
21=x
so, the value of x is 21 cm
and the third side that is AC is equal to 25.
hope it helps.....
please mark as brainlist......