the perimeter of triangle field is 300m and the ratio of sides is 3:5:7( find the sides)
Answers
Step-by-step explanation:
Suppose that the sides in metres are 3x , 5x and 7x.
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .So, the sides of the ∆ are 3 × 20m, 5×20m and 7×20m.
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .So, the sides of the ∆ are 3 × 20m, 5×20m and 7×20m.i.e., 60m , 100m and 140m.
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .So, the sides of the ∆ are 3 × 20m, 5×20m and 7×20m.i.e., 60m , 100m and 140m.We have s = 60+100+140m/2 = 150m
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .So, the sides of the ∆ are 3 × 20m, 5×20m and 7×20m.i.e., 60m , 100m and 140m.We have s = 60+100+140m/2 = 150mArea will be = √150(150-60) (150-100) (150-140)
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .So, the sides of the ∆ are 3 × 20m, 5×20m and 7×20m.i.e., 60m , 100m and 140m.We have s = 60+100+140m/2 = 150mArea will be = √150(150-60) (150-100) (150-140)= √150×90×50×10m^2
Suppose that the sides in metres are 3x , 5x and 7x.Then, we know that 3x+5x+7x = 300 (perimeter of the ∆)therefore, 15x = 300 , which gives x= 20 .So, the sides of the ∆ are 3 × 20m, 5×20m and 7×20m.i.e., 60m , 100m and 140m.We have s = 60+100+140m/2 = 150mArea will be = √150(150-60) (150-100) (150-140)= √150×90×50×10m^2= 1500√3m^2
Answer:
60,100,140
Step-by-step explanation:
let common ratio be X
3x+5x+7x=300
15x=360
x=20
3x=60
5x 100
7x 140