The perimeter of triangle formed by (4,3) (5,1) and (1,-5) is...
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Answer:
√52+√5+√73
Step-by-step explanation:
given that; points A(4,3):B( 5,1): C (1,-5)
AB = √[ (5-4)^2 + (1-3)^2 ]
AB. = √[1+4
AB. = √5
BC. = √[ (1-5)^2 + (-5-1)^2 ]
BC. = √ [16 +36
BC. = √52
AC. = √[ (1-4)^2 + (-5-3)^2]
AC. = √[9+64]
AC. = √73
perimeter of triangle ABC = AB + AC + BC
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