Question

the perimeter of triangle formed by the vertices A (-8, 0) B(0,0) andC(0,6) is

Answer 1

Answer:

perimeter of triangle= a+b+c

Explanation:

first, find the distance between the two points by using the formuy; √(x'-x) + (y'-y)

by doing so,we will get sides as 6,10,8

hence perimeter= 24

Answer 2

Answer:

Let ABC be a triangle having;

A(-8,0) B(0,0) C(0,6)

Using distance formula ;

AB=

$\sqrt{ {(0 - 8)}^{2} + ( {0 - 0)}^{2} } = \sqrt{64 } = 8$

BC=

$\sqrt{ {( 0 - 0)}^{2} + ( {0 - 6)}^{2} } = \sqrt{36} = 6$

CA=

$\sqrt{ {( - 8 - 0)}^{2} + ( {0 - 6)}^{2} } = \sqrt{100} = 10$

therefore,

perimeter of Triangle ABC= AB+BC+CA

= 8+6+10

=24

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