the perimeter of triangle is 288m and the ratio of sides is3:4:5 . Find the area of the triangle
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a+b+c = 288 meters a:b:c = 3:4:5
let a= 3x b = 4 x c = 5 x where x is some number
a+b+c = x(3+4+5) = 12 x So 12 x = 288 meters
x = 24 meters
So a = 72 m b = 96 m c = 120 meters
If the sides of a triangle are in the ratio of 3 : 4 : 5, then it is a right angle trianlgle.
Its area is 1/2 a b . (a, b are smaller sides. c hypotenuse)
So Area = 1/2 72 * 96 = 3456 meter²
IF the sides are not in a right angle triangle, the n find s and use formula for area
let a= 3x b = 4 x c = 5 x where x is some number
a+b+c = x(3+4+5) = 12 x So 12 x = 288 meters
x = 24 meters
So a = 72 m b = 96 m c = 120 meters
If the sides of a triangle are in the ratio of 3 : 4 : 5, then it is a right angle trianlgle.
Its area is 1/2 a b . (a, b are smaller sides. c hypotenuse)
So Area = 1/2 72 * 96 = 3456 meter²
IF the sides are not in a right angle triangle, the n find s and use formula for area
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Answered by
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let the side length be 3x , 4x and 5x
now ,a/q,
3x+ 4x+5x = 288
⇒12x= 288
⇒x= 24
so, length are 72 m, 96 m and 120 m
now we can see that, (120)² = (72)²+ (96)²
so. by Pythagoras theorem , this triangle is right angled triangle,
120 is the length of hypotenuse ,
area = 1/2 ×(96×72)
=3456 m²
now ,a/q,
3x+ 4x+5x = 288
⇒12x= 288
⇒x= 24
so, length are 72 m, 96 m and 120 m
now we can see that, (120)² = (72)²+ (96)²
so. by Pythagoras theorem , this triangle is right angled triangle,
120 is the length of hypotenuse ,
area = 1/2 ×(96×72)
=3456 m²
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